72t^2+74t=0

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Solution for 72t^2+74t=0 equation: 



72t^2+74t=0

a = 72; b = 74; c = 0;
Δ = b2-4ac
Δ = 742-4·72·0
Δ = 5476
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5476}=74$


$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(74)-74}{2*72}=\frac{-148}{144}
=-1+1/36
$


$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(74)+74}{2*72}=\frac{0}{144}
=0
$

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